Files
tictactoe/tictactoe-v2.py
T
2023-03-22 10:35:19 -10:00

124 lines
3.3 KiB
Python

import os
konec = 0
kdoHraje = 0
def init():
global konec, kdoHraje
pole = [[' ', ' ', ' '], [' ', ' ', ' '], [' ', ' ', ' ']]
while konec == 0:
herniKolo(pole)
def clearScreen():
if os.name == "posix":
os.system("clear")
if os.name == "nt":
os.system("cls")
def vypisHru(pole):
for i in range(3):
print(f"[{pole[i][0]}] [{pole[i][1]}] [{pole[i][2]}]")
def check(pole):
# horizontal checking
# 0 is for when 'o's win and 1 is for when 'x's win
for i in range(3):
if pole[i][0] == pole[i][1] == pole[i][2] == 'o':
return 0
if pole[i][0] == pole[i][1] == pole[i][2] == 'x':
return 1
# vertical checking
for i in range(3):
if pole[0][i] == pole[1][i] == pole[2][i] == 'o':
return 0
if pole[0][i] == pole[1][i] == pole[2][i] == 'x':
return 1
# diagonal checking
if pole[0][0] == pole[1][1] == pole[2][2] == 'o':
return 0
if pole[0][0] == pole[1][1] == pole[2][2] == 'x':
return 1
if pole[0][2] == pole[1][1] == pole[2][0] == 'o':
return 0
if pole[0][2] == pole[1][1] == pole[2][0] == 'x':
return 1
# draw checking
# 2 is for when a draw occurs
pocet = 0
for i in range(3):
for j in range(3):
if pole[i][j] == 'o' or pole[i][j] == 'x':
pocet += 1
if pocet == 9:
return 2
def herniKolo(pole):
global konec, kdoHraje
# algorithm steps
#
# 1 clear the screen
# 2 print the current state of the game
# 3 allow for one player or the other to insert coords
# 4 place an 'o' or an 'x' to the coresponding coords
# 5 check if the game should end (if someone won)
# 5.1 if yes -> end the game
# 5.2 if no -> jump to step 1
# step 1 -> clear the screen
#
# cross-platform (Windows, Unix-like OSs)
clearScreen()
# step 2 -> print the current state of the game
vypisHru(pole)
# step 3 -> allow for one player or the other to insert coords
rada, sloupec = map(int, input().split())
# step 4 -> place an 'o' or an 'x' to the coresponding coords
#
# only if there isn't another symbol present and the coords are valid
# the 'o' or 'x' is determined by the kdoHraje variable
# - if it is 0, then an 'o' is placed, if it is 1, an 'x' is placed instead
# the rows and columns are marked 1, 2 and 3, not 0, 1 and 2 as the indexes
# for better user experience
if pole[rada-1][sloupec-1] == ' ' and 1 <= rada <= 3 and 1 <= sloupec <= 3:
print(kdoHraje)
if kdoHraje == 0:
pole[rada-1][sloupec-1] = 'o'
kdoHraje = 1
elif kdoHraje == 1:
pole[rada-1][sloupec-1] = 'x'
kdoHraje = 0
# step 5 -> check if the game should end (if someone won)
vyherce = check(pole)
if vyherce == 0:
# step 5.1 -> if yes -> end the game
clearScreen()
print("Vyhralo o!")
vypisHru(pole)
konec = 1
# step 5.2 -> if no -> jump to step 1
if vyherce == 1:
clearScreen()
print("Vyhralo x!")
vypisHru(pole)
konec = 1
if vyherce == 2:
clearScreen()
print("Remiza!")
vypisHru(pole)
konec = 1
if __name__ == "__main__":
init()